continuing from my prev post

Say u want to find a number that gives the same result when divided by x and when x is subtracted from that... Let, the number be y then y/x=y-x => y=xy-x^2 => y(1-x)=-x^2 => y=(x^2)/(x-1) -----------(1) where x != 1 Got it???? Means if u want to find a number for which [that number]/6=[that number] -6 the just replace the values in equation (1) i.e. y=36/5=7.2

if y=(x^2)/(x-1) then

u can write it as follows

y=(x^2-1+1)/(x-1)

=> y=(x^2-1)/(x-1)+1/(x-1)

=> y=(x+1) + 1/(x-1)

this is the soln u have got... right??? enjoy math.......

**Edited by Arnabmatrix, 03 December 2008 - 03:09 AM.**